(1/16)^2x=4x-5

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Solution for (1/16)^2x=4x-5 equation: 



(1/16)^2x=4x-5

We move all terms to the left:

(1/16)^2x-(4x-5)=0



Domain of the equation: 16)^2x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/16)^2x-(4x-5)=0

We get rid of parentheses

(+1/16)^2x-4x+5=0

We multiply all the terms by the denominator


(+1-4x*16)^2x+5*16)^2x=0

We add all the numbers together, and all the variables

(-4x*16+1)^2x+5*16)^2x=0

Wy multiply elements

(-4x*16+1)^2x+80x=0

We add all the numbers together, and all the variables

80x+(-4x*16+1)^2x=0

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